On the Complexity of Identifying Groups without Abelian Normal Subgroups: Parallel, First Order, and GI-Hardness
By: Joshua A. Grochow, Dan Johnson, Michael Levet
Potential Business Impact:
Tests if two groups are the same faster.
In this paper, we exhibit an $\textsf{AC}^{3}$ isomorphism test for groups without Abelian normal subgroups (a.k.a. Fitting-free groups), a class for which isomorphism testing was previously known to be in $\mathsf{P}$ (Babai, Codenotti, and Qiao; ICALP '12). Here, we leverage the fact that $G/\text{PKer}(G)$ can be viewed as permutation group of degree $O(\log |G|)$. As $G$ is given by its multiplication table, we are able to implement the solution for the corresponding instance of Twisted Code Equivalence in $\textsf{AC}^{3}$. In sharp contrast, we show that when our groups are specified by a generating set of permutations, isomorphism testing of Fitting-free groups is at least as hard as Graph Isomorphism and Linear Code Equivalence (the latter being $\textsf{GI}$-hard and having no known subexponential-time algorithm). Lastly, we show that any Fitting-free group of order $n$ is identified by $\textsf{FO}$ formulas (without counting) using only $O(\log \log n)$ variables. This is in contrast to the fact that there are infinite families of Abelian groups that are not identified by $\textsf{FO}$ formulas with $o(\log n)$ variables (Grochow & Levet, FCT '23).
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